SWEIGH factors for cast iron ("gietijzer") - Printable Version +- PLE forum (http://www.ple4win.nl/forum) +-- Forum: Pipeline strength and stability analysis (http://www.ple4win.nl/forum/forumdisplay.php?fid=3) +--- Forum: General Technical Matters (http://www.ple4win.nl/forum/forumdisplay.php?fid=24) +--- Thread: SWEIGH factors for cast iron ("gietijzer") (/showthread.php?tid=432) SWEIGH factors for cast iron ("gietijzer") - Dr. J Foerster - 07-05-2014 As an addition to the question about SWEIGH factors for PE: If materials have different factors for axial and tangential directions (such as nodular cast iron) then the following should be applied: The axial factor should be used for SXUB1, SXUBH, SXIOSH and SXIORA, the tangential factor should be used for SFIOSH and SFIORA, all other factors should be set to 1. RE: SWEIGH factors for cast iron ("gietijzer") - shaswin - 05-08-2014 Jens, This knowhow should also be included in the helpfile of PLE (upcoming version Ple4Win v4.3.0). Three examples can be given: - the two discussed examples from post #1: PE and nodular cast iron; - the axial and tangential factors are 1 for steel. RE: SWEIGH factors for cast iron ("gietijzer") - Dr. J Foerster - 08-08-2014 We will include this information in the help file. RE: SWEIGH factors for cast iron ("gietijzer") - shaswin - 08-08-2014 (08-08-2014, 10:46 AM)Dr. J Foerster Wrote: We will include this information in the help file. Maybe the SWEIGH correction factors for miter bends can also be included, see this topic. RE: SWEIGH factors for cast iron ("gietijzer") - Bas - 04-12-2014 What happens if you have for example PE with mitre bends? Multiply the calculated mitre bend values for SXUBH, SXIOSH, SFIOSH with the factor 0,65? RE: SWEIGH factors for cast iron ("gietijzer") - shaswin - 04-12-2014 Bas, I have made a screenshot of the SWEIGH table (PE 100 pipe with miter bend) for you. [attachment=581] In this case Ident "recht1" and "recht2" are straight pipes. "bocht_s" is the start of the miter bend and "bocht_e" is the end of the miter bend. 0.542 = 0.75/0.9 * 0.65 (within the miter bend; see more information about the factor in this topic) This reduction is only valid for pure out of plane bends (not valid for sleeping miter bends).